Skip to main content

Posts

Showing posts from November 28, 2012

Problem Solving : Permutation and combination Problem 3: If the letter of the word SEQUESTERED are arranged in all possible ways and these words are written out as in a dictionary form, then what is the 50th rank of the word SEQUESTERED is ?

If the letter of the word SEQUESTERED are arranged in all possible ways and these words are written out as in a dictionary form, then what is the 50th rank of the word SEQUESTERED is ? Solution: So the word SEQUESTERED can be arranged in dictionary form of letters as D E E E E Q R S S T U Hence the number of words begin with DEEEEQR = 4! / 2! =12 and  the number of words begin with  DEEEEQS = 4! =24 the number of words begin with  DEEEEQT = 4! / 2! =12 12+24+12 =48 so next word U becomes last word hence next words are 49 and 50 will  be DEEEEQURSST is 49th word and DEEEEQURSTS is the 50th word and the answer -->  50th rank of the word SEQUESTERED is " DEEEEQURSTS  "

Cisco CCNA 1

Click here to view more Videos

Quantitative Aptitude : Problem Solving Skills

Click here to view more Videos

Problem Solving : Permutation and combination Problem 2: If the letter of the word VERMA are arranged in all possible ways and these words are written out as in a dictionary form, then what is the rank of the word VERMA is ?

If the letter of the word VERMA are arranged in all possible ways and these words are written out as in a dictionary form, then what is the rank of the word VERMA is ? Solution: so the word VERMA letters of V, E, R, M, A In alphabetical order A, E, M, R, V So the number of words begin with A = 4! (leave A and consider remaining letters E, M, R, V) and the number of words begin with  E = 4! (leave A and consider remaining letters A, M, R, V) and the number of words begin with  M  = 4! (leave A and consider remaining letters E, A, R, V) and the number of words begin with  R  = 4! (leave A and consider remaining letters E, M, A, V) after the word begins with V so here after consider two or more words combinations So the number of words begin with VA   = 3! (leave v and A and consider remaining 3 letters E,M, R) VE becomes next character after VA set so below are the dictionary arrangement goes 1) VEAMR 2) VEARM 3) VEMAR 4) VEMRA 5) VERAM finally ...