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Problem Solving : Cryptarithmatic Problem 1 :Find the value of P from [ A L E * R U M = E R M P N E]

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ALE * RUM ------------ W I N E W U W L E W W E -------------------- E R M P N E ______________ Here is the solution: 0 to 9 , 10 numbers Should be replaced with those following Characters A, L, E, R, U, M, W, I, N, P so 10 characters replaced with 10 digits from 0 to 9 Consider M * ALE = WINE and U * ALE = WUWL and R * ALE = EWWE See in last R *ALE = EWWE R * E = E will be last digit so it possible only by multiplication of 5 with odd values so 1 * 5 or  3* 5 or 7*5 and 9*5 = last unit digit always 5 so E = 5 but 5* 5 not possible because R is not  equal to W.....and look at multiplied value N + L = N so any value on addition with 0 will give  you result as same hence N + 0 = N then L = 0 so remaining A and R are left R possible values are R = 1, 3, 7, 9 but 1 is not possible because  1 * ALE is equal to ALE and R = 3, 7, 9 are possible...... Already we know that E = 5 and L = 0 then R * A05 = 5WW5 (apply logic her...
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Algorithm Videos Set 1

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Problem Solving : Permutation and combination Problem 3: If the letter of the word SEQUESTERED are arranged in all possible ways and these words are written out as in a dictionary form, then what is the 50th rank of the word SEQUESTERED is ?

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If the letter of the word SEQUESTERED are arranged in all possible ways and these words are written out as in a dictionary form, then what is the 50th rank of the word SEQUESTERED is ? Solution: So the word SEQUESTERED can be arranged in dictionary form of letters as D E E E E Q R S S T U Hence the number of words begin with DEEEEQR = 4! / 2! =12 and  the number of words begin with  DEEEEQS = 4! =24 the number of words begin with  DEEEEQT = 4! / 2! =12 12+24+12 =48 so next word U becomes last word hence next words are 49 and 50 will  be DEEEEQURSST is 49th word and DEEEEQURSTS is the 50th word and the answer -->  50th rank of the word SEQUESTERED is " DEEEEQURSTS  "
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Cisco CCNA 1

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Quantitative Aptitude : Problem Solving Skills

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Problem Solving : Permutation and combination Problem 2: If the letter of the word VERMA are arranged in all possible ways and these words are written out as in a dictionary form, then what is the rank of the word VERMA is ?

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If the letter of the word VERMA are arranged in all possible ways and these words are written out as in a dictionary form, then what is the rank of the word VERMA is ? Solution: so the word VERMA letters of V, E, R, M, A In alphabetical order A, E, M, R, V So the number of words begin with A = 4! (leave A and consider remaining letters E, M, R, V) and the number of words begin with  E = 4! (leave A and consider remaining letters A, M, R, V) and the number of words begin with  M  = 4! (leave A and consider remaining letters E, A, R, V) and the number of words begin with  R  = 4! (leave A and consider remaining letters E, M, A, V) after the word begins with V so here after consider two or more words combinations So the number of words begin with VA   = 3! (leave v and A and consider remaining 3 letters E,M, R) VE becomes next character after VA set so below are the dictionary arrangement goes 1) VEAMR 2) VEARM 3) VEMAR 4) VEMRA 5) VERAM finally ...
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