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Advanced Generalized Starting number formula for odd/even numbered Magic Square Boxes and It's Algorithm

I've posted my Previous Formula here  http://www.kumaran198726.com/2012/07/magic-square-box.html Here I'll add my updated formula and algorithms SnapShots 1)  Previous Formula 2) 3)  4) 5) 6) 7) 8) 9) 10) 11) New and Advanced formula 12) 13) 14) 15) 16) 17) 18) 19) Algorithms and Flow Chart 20) 21) 22) 23) 24) 25) 26) A single Paper SnapShots Page 1 Page 2 Page 3 Page 4 Page 5 page 6 Page 7 Page 8 Page 9 Page 10 Page 11 Page 12 Page 13

Problem Solving : Cryptarithmatic Problem 1 :Find the value of P from [ A L E * R U M = E R M P N E]

ALE * RUM ------------ W I N E W U W L E W W E -------------------- E R M P N E ______________ Here is the solution: 0 to 9 , 10 numbers Should be replaced with those following Characters A, L, E, R, U, M, W, I, N, P so 10 characters replaced with 10 digits from 0 to 9 Consider M * ALE = WINE and U * ALE = WUWL and R * ALE = EWWE See in last R *ALE = EWWE R * E = E will be last digit so it possible only by multiplication of 5 with odd values so 1 * 5 or  3* 5 or 7*5 and 9*5 = last unit digit always 5 so E = 5 but 5* 5 not possible because R is not  equal to W.....and look at multiplied value N + L = N so any value on addition with 0 will give  you result as same hence N + 0 = N then L = 0 so remaining A and R are left R possible values are R = 1, 3, 7, 9 but 1 is not possible because  1 * ALE is equal to ALE and R = 3, 7, 9 are possible...... Already we know that E = 5 and L = 0 then R * A05 = 5WW5 (apply logic her...

Algorithm Videos Set 1

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Problem Solving : Permutation and combination Problem 3: If the letter of the word SEQUESTERED are arranged in all possible ways and these words are written out as in a dictionary form, then what is the 50th rank of the word SEQUESTERED is ?

If the letter of the word SEQUESTERED are arranged in all possible ways and these words are written out as in a dictionary form, then what is the 50th rank of the word SEQUESTERED is ? Solution: So the word SEQUESTERED can be arranged in dictionary form of letters as D E E E E Q R S S T U Hence the number of words begin with DEEEEQR = 4! / 2! =12 and  the number of words begin with  DEEEEQS = 4! =24 the number of words begin with  DEEEEQT = 4! / 2! =12 12+24+12 =48 so next word U becomes last word hence next words are 49 and 50 will  be DEEEEQURSST is 49th word and DEEEEQURSTS is the 50th word and the answer -->  50th rank of the word SEQUESTERED is " DEEEEQURSTS  "

Cisco CCNA 1

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Quantitative Aptitude : Problem Solving Skills

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